tidyNode::isAsp
(PHP 5 >= 5.0.1, PHP 7)
tidyNode :: isAsp - 检查此节点是否为ASP
描述
bool tidyNode::isAsp ( void )判断当前节点是否为ASP。
返回值
TRUE如果节点是ASP，FALSE则返回，否则返回。
例子
示例＃1从混合HTML文档中提取ASP代码
<?php
$html = <<< HTML
<html><head>
<?php echo '<title>title</title>'; ?>
<#
/* JSTE code */
alert('Hello World');
#>
</head>
<body>
<?php
// PHP code
echo 'hello world!';
?>
<%
/* ASP code */
response.write("Hello World!")
%>
<!-- Comments -->
Hello World
</body></html>
Outside HTML
HTML;
$tidy = tidy_parse_string($html);
$num = 0;
get_nodes($tidy->html());
function get_nodes($node) {
// check if the current node is of requested type
if($node->isAsp()) {
echo "\n\n# asp node #" . ++$GLOBALS['num'] . "\n";
echo $node->value;
}
// check if the current node has childrens
if($node->hasChildren()) {
foreach($node->child as $child) {
get_nodes($child);
}
}
}
?>上面的例子将输出：
# asp node #1
<%
/* ASP code */
response.write("Hello World!")
%>← tidyNode::hasSiblings
tidyNode::isComment →
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